Introduction to trinomial solution:
A polynomial with three terms is known as trinomial. One of the three terms is a constant and one of the remaining terms is a constant with a variable and another term is a constant with square of a variable. The constant is an optional. The roots of the trinomial are a solution for the given trinomial. The methods to solve a trinomial are by using quadratic formula or by using factoring method.
General form – Trinomial solution:
The general form of a trinomial is ax ^2+bx+c=0. In this x is a variable and a, b and c are constants.
The value of x is trinomial solution.
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Example problems – Trinomial solution:
Example 1 – Trinomial solution:
Solve the trinomial x ^2+8x+15=0.
Solution:
The given trinomial is x ^2+6x+9=0.
The given trinomial can be written as,
x ^2+3x+3x+9=0.
Take x as common from first two terms
x(x+3)+3x+9=0
Take 3 as common from last two terms
x(x+3)+3(x+3)=0
Take (x+3) as common
(x+3)(x+3)=0
The above product of monomials can be written as
x+3 = 0 and x+3=0
Now solve the above terms for x
So, `x=-3` and `x=-3`
The given trinomial’s solutions are -3 and -3.
So, the answer is -3.
Example 2 – Trinomial solution:
Solve the trinomial x ^2+12x+20=0.
Solution:
The given trinomial is x ^2+12x+20=0.
The given trinomial can be written as,
x ^2+10x+2x+20=0.
Take x as common from first two terms
x(x+10)+2x+20=0
Take 3 as common from last two terms
x(x+10)+2(x+10)=0
Take (x+10) as common
(x+10)(x+2)=0
The above product of monomials can be written as
x+10 = 0 and x+2=0
Now solve the above terms for x
So, `x=-10` and `x=-2`
The given trinomial’s solutions are -10 and -2.
Example 3 – Trinomial solution:
Solve the trinomial 2x ^2+20x+50=0.
Solution:
The given trinomial is 2x ^2+20x+50=0.
The given trinomial can be written as,
2x ^2+10x+10x+50=0.
Take 2x as common from first two terms
2x(x+5)+10x+50=0
Take 10 as common from last two terms
2x(x+5)+10(x+5)=0
Take (x+5) as common
(x+5)(2x+10)=0
The above product of monomials can be written as
x+5 = 0 and 2x+10=0
Now solve the above terms for x
So, `x=-5 ` and `x=-5`
The given trinomial’s solutions are -5 and -5.
So the solution is -5.
A polynomial with three terms is known as trinomial. One of the three terms is a constant and one of the remaining terms is a constant with a variable and another term is a constant with square of a variable. The constant is an optional. The roots of the trinomial are a solution for the given trinomial. The methods to solve a trinomial are by using quadratic formula or by using factoring method.
General form – Trinomial solution:
The general form of a trinomial is ax ^2+bx+c=0. In this x is a variable and a, b and c are constants.
The value of x is trinomial solution.
Is this topic simplify fractions online hard for you? Watch out for my coming posts.
Example problems – Trinomial solution:
Example 1 – Trinomial solution:
Solve the trinomial x ^2+8x+15=0.
Solution:
The given trinomial is x ^2+6x+9=0.
The given trinomial can be written as,
x ^2+3x+3x+9=0.
Take x as common from first two terms
x(x+3)+3x+9=0
Take 3 as common from last two terms
x(x+3)+3(x+3)=0
Take (x+3) as common
(x+3)(x+3)=0
The above product of monomials can be written as
x+3 = 0 and x+3=0
Now solve the above terms for x
So, `x=-3` and `x=-3`
The given trinomial’s solutions are -3 and -3.
So, the answer is -3.
Example 2 – Trinomial solution:
Solve the trinomial x ^2+12x+20=0.
Solution:
The given trinomial is x ^2+12x+20=0.
The given trinomial can be written as,
x ^2+10x+2x+20=0.
Take x as common from first two terms
x(x+10)+2x+20=0
Take 3 as common from last two terms
x(x+10)+2(x+10)=0
Take (x+10) as common
(x+10)(x+2)=0
The above product of monomials can be written as
x+10 = 0 and x+2=0
Now solve the above terms for x
So, `x=-10` and `x=-2`
The given trinomial’s solutions are -10 and -2.
Example 3 – Trinomial solution:
Solve the trinomial 2x ^2+20x+50=0.
Solution:
The given trinomial is 2x ^2+20x+50=0.
The given trinomial can be written as,
2x ^2+10x+10x+50=0.
Take 2x as common from first two terms
2x(x+5)+10x+50=0
Take 10 as common from last two terms
2x(x+5)+10(x+5)=0
Take (x+5) as common
(x+5)(2x+10)=0
The above product of monomials can be written as
x+5 = 0 and 2x+10=0
Now solve the above terms for x
So, `x=-5 ` and `x=-5`
The given trinomial’s solutions are -5 and -5.
So the solution is -5.
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