7th and 8th grade math:
In this article we discuss about solving problems in 7th and 8th grade math. In this article we are going to discuss for solving problems in 7th and 8th grade math topics. In our day to day we are using arithmetical concepts often. Solving problems in 7th and 8th grade math covers following chapters
Numbers
Measures
Algebra
Geometry
The solving problems in 7th and 8th grade math topics are given below.
Example problems in 7th and 8th grade math:
Example 1:
Simplify the given expression `((-80) * (3))/ (- 2)^2`
Solution:
Given expression `(-80) * (3)/ (- 2)^2`
`(-80) * (3) / (4)` =` - (80 * 3)/ (4)` = -60
Solution is -60.
Example 2:
Simplify the given expression 8 + (5 – 2) =?
Solution:
Given expression 8+ (5-2)
8 + (5 – 2) = 8+3 = 11
Solution is 11.
Example 3:
Davit sells a house through a broker for Rs.5, 00,000 paying a brokerage of 2%. Find the amount of brokerage.
Solution:
The selling price of the house =Rs 500000
Rate of brokerage = 2%
Amount of brokerage = 2/100 * 500000
= 10000
The amount of brokerage = Rs 10000
Example 4:
Radius of a sector is 10 cm. Its arc length is 18 cm. Find its perimeter.
Solution:
Given, r = 10cm and l = 18 cm
P = l+2r units.
= 18 + 2 * 10 cm.
= 18+20 = 38cm.
P = 38cm.
The perimeter is 38cm.
Is this topic formula for square footage hard for you? Watch out for my coming posts.
Example 5:
Find the volume of the right prism whose are of the base is 350 cm2 and height is 24 cm.
Solution:
Given that area of the base, A = 350 cm2 and height (h) of the prism = 24 cm.
Volume of the right prism = Area of the base * height cu units.
= A h
= 350 * 24 = 8400
Volume = 8400 cm3
Example 6:
Find the circumference of a circle whose radius is 7cm.
Solution:
Radius r = 7cm
Circumference, C = 2 pi r
= 2 * 22/7 * 7
= 44
Circumference of the circle = 44cm.
Example 7:
One third of a certain number is 9. Find the number.
Solution:
Let the unknown number be m. One third of m is 1/3 * m
But 1/3 m = 9
m = 9 * 3 (by rule 3)
m = 27
The number is 27.
Example 8:
Sum of 3 consecutive odd numbers is 51. Find the numbers.
Solution:
Framing the equation:
Let the first odd numbers be x.
Then the second and third odd numbers are (x+2) and (x+4)
There sum is 51.
x+(x+2)+(x+4) = 51
x+x+2+x+4 = 51
3x + 6 = 51(adding the like terms)
3x+6 = 51 is the required equation.
Solving the equation:
3x+6 = 51
3x = 51 – 6 (by rule 1)
= 45
x = 45 * 1/3 (by rule 3)
x = 15
The consecutive odd numbers are x, (x=2), (x=4)
15, (15+2) and (15+4)
The required numbers are 15, 17 and 19.
In this article we discuss about solving problems in 7th and 8th grade math. In this article we are going to discuss for solving problems in 7th and 8th grade math topics. In our day to day we are using arithmetical concepts often. Solving problems in 7th and 8th grade math covers following chapters
Numbers
Measures
Algebra
Geometry
The solving problems in 7th and 8th grade math topics are given below.
Example problems in 7th and 8th grade math:
Example 1:
Simplify the given expression `((-80) * (3))/ (- 2)^2`
Solution:
Given expression `(-80) * (3)/ (- 2)^2`
`(-80) * (3) / (4)` =` - (80 * 3)/ (4)` = -60
Solution is -60.
Example 2:
Simplify the given expression 8 + (5 – 2) =?
Solution:
Given expression 8+ (5-2)
8 + (5 – 2) = 8+3 = 11
Solution is 11.
Example 3:
Davit sells a house through a broker for Rs.5, 00,000 paying a brokerage of 2%. Find the amount of brokerage.
Solution:
The selling price of the house =Rs 500000
Rate of brokerage = 2%
Amount of brokerage = 2/100 * 500000
= 10000
The amount of brokerage = Rs 10000
Example 4:
Radius of a sector is 10 cm. Its arc length is 18 cm. Find its perimeter.
Solution:
Given, r = 10cm and l = 18 cm
P = l+2r units.
= 18 + 2 * 10 cm.
= 18+20 = 38cm.
P = 38cm.
The perimeter is 38cm.
Is this topic formula for square footage hard for you? Watch out for my coming posts.
Example 5:
Find the volume of the right prism whose are of the base is 350 cm2 and height is 24 cm.
Solution:
Given that area of the base, A = 350 cm2 and height (h) of the prism = 24 cm.
Volume of the right prism = Area of the base * height cu units.
= A h
= 350 * 24 = 8400
Volume = 8400 cm3
Example 6:
Find the circumference of a circle whose radius is 7cm.
Solution:
Radius r = 7cm
Circumference, C = 2 pi r
= 2 * 22/7 * 7
= 44
Circumference of the circle = 44cm.
Example 7:
One third of a certain number is 9. Find the number.
Solution:
Let the unknown number be m. One third of m is 1/3 * m
But 1/3 m = 9
m = 9 * 3 (by rule 3)
m = 27
The number is 27.
Example 8:
Sum of 3 consecutive odd numbers is 51. Find the numbers.
Solution:
Framing the equation:
Let the first odd numbers be x.
Then the second and third odd numbers are (x+2) and (x+4)
There sum is 51.
x+(x+2)+(x+4) = 51
x+x+2+x+4 = 51
3x + 6 = 51(adding the like terms)
3x+6 = 51 is the required equation.
Solving the equation:
3x+6 = 51
3x = 51 – 6 (by rule 1)
= 45
x = 45 * 1/3 (by rule 3)
x = 15
The consecutive odd numbers are x, (x=2), (x=4)
15, (15+2) and (15+4)
The required numbers are 15, 17 and 19.
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